Select the correct answerWhat will be the output of the following Java code? class Area { public static void main(String args[]) { double radii, pi, area; radii = 6.6; pi = 3.14; area = pi * radii * radii; System.out.println(area); } }Options136136.7784136.77136.7760000
Question
Select the correct answerWhat will be the output of the following Java code? class Area { public static void main(String args[]) { double radii, pi, area; radii = 6.6; pi = 3.14; area = pi * radii * radii; System.out.println(area); } }Options136136.7784136.77136.7760000
Solution
The output of the Java code will be 136.7784.
Here's the step-by-step explanation:
-
The code defines a class named
Areawith amainmethod. Themainmethod is the entry point for any Java application. -
Inside the
mainmethod, three double variables are declared:radii,pi, andarea. -
The
radiivariable is assigned a value of 6.6. -
The
pivariable is assigned a value of 3.14. -
The
areavariable is calculated aspi * radii * radii, which is the formula for the area of a circle. In this case, it will be3.14 * 6.6 * 6.6. -
The
System.out.println(area);statement prints the value of theareavariable to the console. -
When you calculate
3.14 * 6.6 * 6.6, the result is approximately136.7784.
So
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