Which of the following relationships is valid for the speed, v of a cyclotron of radius R if a charge q of mass m is in a magnetic field of magnetic flux density B?*1 pointv = BRq/mv = BmR/qv = Bmq/Rv = Rqm/B
Question
Which of the following relationships is valid for the speed, v of a cyclotron of radius R if a charge q of mass m is in a magnetic field of magnetic flux density B?*1 pointv = BRq/mv = BmR/qv = Bmq/Rv = Rqm/B
Solution 1
The correct relationship for the speed, v, of a cyclotron of radius R, with a charge q of mass m in a magnetic field of magnetic flux density B is:
v = BRq/m
This is derived from the equation for the force on a charged particle moving in a magnetic field, F = qvB. In a cyclotron, this force provides the centripetal force for circular motion, F = mv^2/R. Equating these two expressions and solving for v gives v = BRq/m.
Solution 2
The correct relationship for the speed, v, of a cyclotron of radius R, with a charge q of mass m in a magnetic field of magnetic flux density B is:
v = BRq/m
This is derived from the equation for the force on a charged particle moving in a magnetic field, F = qvB. In a cyclotron, this force is providing the centripetal force for circular motion, so F = mv^2/R. Equating these gives qvB = mv^2/R, which simplifies to v = BRq/m.
Solution 3
The relationship between the speed (v) of a cyclotron, its radius (R), the charge (q) of the particle, the mass (m) of the particle, and the magnetic flux density (B) is given by the equation:
v = qBR/m
This equation is derived from the Lorentz force law, which states that the force on a charged particle moving in a magnetic field is equal to the charge times the velocity of the particle times the magnetic field. In a cyclotron, this force is always perpendicular to the velocity of the particle, causing it to move in a circular path. The speed of the particle is then given by the ratio of the magnetic force to the mass of the particle, which gives the above equation.
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