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A sample of the diluted coffee drink was run through the HPLC column under identical conditions to those used to obtain the calibration curve.The peak area obtained for this diluted sample was 2400 arbitrary units.Description of calibration curve - (x - concentration,y - peak area) - (0.010,1000), (0.020,2000), (0.030,3000), (0.040,4000), (0.050,5000),(0.060,6000)a) What is the purpose of creating a calibration curve? (1 mark)b) Determine the concentration of caffeine in g L-1, of the diluted sample of coffee drink. (1 mark)c) Determine the concentration of the caffeine in the original coffee drink in units of M. SHOW YOUR WORKING. (2 marks)d) Determine the mass of the caffeine, in grams, in 350 mL of the undiluted coffee drink. SHOW YOUR WORKING. (1 mark)

Question

A sample of the diluted coffee drink was run through the HPLC column under identical conditions to those used to obtain the calibration curve.The peak area obtained for this diluted sample was 2400 arbitrary units.Description of calibration curve - (x - concentration,y - peak area) - (0.010,1000), (0.020,2000), (0.030,3000), (0.040,4000), (0.050,5000),(0.060,6000)a) What is the purpose of creating a calibration curve? (1 mark)b) Determine the concentration of caffeine in g L-1, of the diluted sample of coffee drink. (1 mark)c) Determine the concentration of the caffeine in the original coffee drink in units of M. SHOW YOUR WORKING. (2 marks)d) Determine the mass of the caffeine, in grams, in 350 mL of the undiluted coffee drink. SHOW YOUR WORKING. (1 mark)

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Solution

a) The purpose of creating a calibration curve is to establish a relationship between known concentrations of a substance and the response of the instrument (in this case, peak area). This allows for the determination of the concentration of the same substance in an unknown sample by comparing its response to the calibration curve.

b) The calibration curve is linear, with a slope of 1000 units per 0.01 g/L. Therefore, the concentration of the diluted sample can be calculated as follows:

2400 units = 1000 units/0.01 g/L * concentration

Solving for concentration gives:

Concentration = 2400 units / (1000 units/0.01 g/L) = 0.024 g/L

c) To convert the concentration from g/L to M (molarity), we need to know the molar mass of caffeine, which is approximately 194.19 g/mol.

Concentration in M = 0.024 g/L / 194.19 g/mol = 1.24 x 10^-4 M

d) To find the mass of caffeine in 350 mL of the undiluted coffee drink, we first need to convert the volume to liters:

350 mL = 0.35 L

Then we multiply the volume by the concentration to get the mass:

Mass = 0.35 L * 0.024 g/L = 0.0084 g

This problem has been solved

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