An x m high, 6 m wide rectangular plate fully emerges in the freshwater channel, as shown in the figure. The plate is hinged about a horizontal axis along its upper edge through point A and is restrained from opening by a fixed ridge at point B. Determine the centre of pressure or the line of action of the hydrostatic force from the Bottom level of water in 'meter' unit.P.S: The drawing is not drawn on an accurate scale.Here, x =6 m

The center of pressure is the point where the total sum of a pressure field acts on a body, causing a force to act through that point. The calculation for the center of pressure is the depth of the centroid plus the moment of inertia of the shape about the centroid divided by the area of the shape times the depth of the centroid.

Given that the rectangular plate is fully submerged in water, the depth of the centroid (h) is half of the height of the rectangle, which is x/2 = 6/2 = 3m.

The moment of inertia (I) for a rectangle about its base is (bh^3)/12, where b is the width and h is the height. So, I = (66^3)/12 = 108 m^4.

The area (A) of the rectangle is the height times the width, so A = 6*6 = 36 m^2.

Substituting these values into the formula for the center of pressure, we get:

Center of Pressure = h + (I/Ah) = 3 + (108/36*3) = 3 + 1 = 4m.

So, the center of pressure or the line of action of the hydrostatic force from the bottom level of water is 4 meters.

The center of pressure is the point where the total sum of a pressure field acts on a body, causing a force to act through that point. The calculation for the center of pressure is the depth of the centroid plus the moment of inertia of the shape about the centroid, divided by the area of the shape times the depth of the centroid.

Given that the plate is a rectangle, the depth of the centroid (h) is half of the height of the rectangle, so h = x/2 = 6/2 = 3 m.

The moment of inertia (I) for a rectangle is (bh^3)/12, where b is the width and h is the height. So, I = (66^3)/12 = 108 m^4.

The area (A) of the rectangle is the width times the height, so A = 6*6 = 36 m^2.

Substituting these values into the formula for the center of pressure, we get:

Center of Pressure = h + (I/(Ah)) = 3 + (108/(363)) = 3 + 1 = 4 m.

So, the center of pressure or the line of action of the hydrostatic force from the bottom level of water is 4 meters.