Debug the code: #include <iostream> class Base { public: virtual void print() { std::cout << "Base\n"; } }; class Derived : public Base { public: void print() override { std::cout << "Derived\n"; } }; int main() { Base* ptr = new Derived(); ptr->print(); delete ptr; return 0; } (2 Points) a) Base b) Derived c) Compilation Error d) Runtime Error
Question
Debug the code:
#include <iostream>
class Base {
public:
virtual void print() { std::cout << "Base\n"; }
};
class Derived : public Base {
public:
void print() override { std::cout << "Derived\n"; }
};
int main() {
Base* ptr = new Derived();
ptr->print();
delete ptr;
return 0;
} (2 Points)
a) Base
b) Derived
c) Compilation Error
d) Runtime Error
Solution
The code is correct and there is no need for debugging. When the code is run, it will print "Derived". This is because the print() function in the Derived class overrides the print() function in the Base class. So, when ptr->print() is called, the print() function of the Derived class is executed. Therefore, the correct answer is b) Derived.
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