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When Dale was building his fish pond, he needed a truck to carry away the soil and rocks that he dug from the hole. The hole was 2.4 m by 1.9 m by 1.6 m. The weight of the soil and rocks averages 112 pounds per cubic foot. (Use 1 m = 3.3 ft)What will be the weight, in pounds, of the soil and rocks dug out for the fish pound?(Round your final answer only to the nearest whole number and put no units in the blank.)

Question

When Dale was building his fish pond, he needed a truck to carry away the soil and rocks that he dug from the hole. The hole was 2.4 m by 1.9 m by 1.6 m. The weight of the soil and rocks averages 112 pounds per cubic foot. (Use 1 m = 3.3 ft)What will be the weight, in pounds, of the soil and rocks dug out for the fish pound?(Round your final answer only to the nearest whole number and put no units in the blank.)

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Solution

First, we need to convert the dimensions of the hole from meters to feet, since the weight of the soil and rocks is given in pounds per cubic foot.

We do this by multiplying each dimension by 3.3 (since 1 meter = 3.3 feet):

2.4 m * 3.3 ft/m = 7.92 ft 1.9 m * 3.3 ft/m = 6.27 ft 1.6 m * 3.3 ft/m = 5.28 ft

Next, we find the volume of the hole in cubic feet by multiplying the length, width, and height together:

7.92 ft * 6.27 ft * 5.28 ft = 261.63 cubic feet

Finally, we multiply the volume of the hole by the weight of the soil and rocks per cubic foot to find the total weight:

261.63 cubic feet * 112 pounds/cubic foot = 29262.56 pounds

Rounding to the nearest whole number, the weight of the soil and rocks dug out for the fish pond is approximately 29263 pounds.

This problem has been solved

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