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A pole of height h = 50 ft has a shadow of length l = 50√3 ft. at a particular instant of time. Find the angle of elevation (in degrees) of the sun at this point of time.*A. 30 degreesB. 45 degreesC. 60 degreesD. 90 degrees

Question

A pole of height h = 50 ft has a shadow of length l = 50√3 ft. at a particular instant of time. Find the angle of elevation (in degrees) of the sun at this point of time.*A. 30 degreesB. 45 degreesC. 60 degreesD. 90 degrees

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Solution

The angle of elevation can be found using the concept of trigonometry. In this case, we can use the tangent of the angle which is the ratio of the opposite side to the adjacent side in a right triangle.

Here, the height of the pole is the opposite side (h = 50 ft) and the length of the shadow is the adjacent side (l = 50√3 ft).

So, tan(θ) = h/l = 50/50√3 = 1/√3.

Now, we need to find the angle whose tangent is 1/√3. If we look at the standard angles, we know that tan(30 degrees) = 1/√3.

So, the angle of elevation of the sun at this point of time is 30 degrees. Therefore, the correct answer is A. 30 degrees.

This problem has been solved

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