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A chemist dissolves 762.mg of pure nitric acid in enough water to make up 90.mL of solution. Calculate the pH of the solution. Round your answer to 2 significant decimal places.

Question

A chemist dissolves 762.mg of pure nitric acid in enough water to make up 90.mL of solution. Calculate the pH of the solution. Round your answer to 2 significant decimal places.

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Solution

To calculate the pH of the solution, we need to follow these steps:

  1. Convert the mass of nitric acid (HNO3) to moles. Nitric acid has a molar mass of approximately 63.01 g/mol. So, 762 mg is 0.762 g. Therefore, the number of moles of HNO3 is 0.762 g / 63.01 g/mol = 0.0121 mol.

  2. Calculate the molarity (concentration) of the solution. Molarity is defined as the number of moles of solute per liter of solution. Since we have 90 mL of solution, this is 0.09 L. Therefore, the molarity of the HNO3 solution is 0.0121 mol / 0.09 L = 0.134 M.

  3. Nitric acid is a strong acid, which means it completely ionizes in water. Therefore, the concentration of H+ ions is equal to the concentration of the nitric acid, which is 0.134 M.

  4. The pH of a solution is calculated using the formula pH = -log[H+]. Therefore, the pH of the solution is -log(0.134) = 0.87 (rounded to two decimal places).

This problem has been solved

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