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If f(x) = 3x2, then F(x) =A. 6xB. x3C. x3 + CD. 6x + C

Question

If f(x) = 3x2, then F(x) =A. 6xB. x3C. x3 + CD. 6x + C

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Solution

To solve the problem, we need to find the antiderivative (or indefinite integral) of the function f(x)=3x2 f(x) = 3x^2 .

Step 1: Identify the function to integrate. f(x)=3x2 f(x) = 3x^2

Step 2: Use the power rule for integration, which states that the integral of xn x^n is xn+1n+1 \frac{x^{n+1}}{n+1} , where n1 n \neq -1 .

Step 3: Apply the power rule to 3x2 3x^2 . 3x2dx=3x2dx \int 3x^2 \, dx = 3 \int x^2 \, dx

Step 4: Integrate x2 x^2 . x2dx=x2+12+1=x33 \int x^2 \, dx = \frac{x^{2+1}}{2+1} = \frac{x^3}{3}

Step 5: Multiply by the constant 3. 3x33=x3 3 \cdot \frac{x^3}{3} = x^3

Step 6: Add the constant of integration C C . F(x)=x3+C F(x) = x^3 + C

Therefore, the correct answer is: C. x3+C \text{C. } x^3 + C

This problem has been solved

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