47. The following code will point1.if(new Boolean("true") == new Boolean("true"))2. System.out.println("True");3. else4. System.out.println("False");A. Compilation errorB. No compilation error , but runtime exceptionC. Prints "True"D. Prints "False"E. Depends on the particular implementation of the Java Virtual Machine
Question
- The following code will point1.if(new Boolean("true") == new Boolean("true"))2. System.out.println("True");3. else4. System.out.println("False");A. Compilation errorB. No compilation error , but runtime exceptionC. Prints "True"D. Prints "False"E. Depends on the particular implementation of the Java Virtual Machine
Solution
The given code snippet checks if two Boolean objects with the values "true" are equal. Let's analyze it step by step:
-
The code compares two Boolean objects using the equality operator (==). This operator checks if the two objects refer to the same memory location, not if their values are equal.
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If the comparison in step 1 evaluates to true, the code will execute the following line:
System.out.println("True");
This line will print "True" to the console.
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If the comparison in step 1 evaluates to false, the code will execute the following line:
System.out.println("False");
This line will print "False" to the console.
Based on the given code, the output will be "True" because the comparison of the two Boolean objects will evaluate to true.
Therefore, the correct answer is C. Prints "True".
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