During a dynamometer test a 4 cylinder, 4 stroke diesel engine develops an indicated meaneffective pressure of 850 KN/m2 at an engine speed of 2000rpm. The engine has a bore of93mm and stroke of 91mm. The test runs for 5 min, during which time 0.8kg of fuel isconsumed. Mechanical efficiency is 83%. Calorific value of the fuel is 43MJ/kg.Calculatei) The indicated power
Question
During a dynamometer test a 4 cylinder, 4 stroke diesel engine develops an indicated meaneffective pressure of 850 KN/m2 at an engine speed of 2000rpm. The engine has a bore of93mm and stroke of 91mm. The test runs for 5 min, during which time 0.8kg of fuel isconsumed. Mechanical efficiency is 83%. Calorific value of the fuel is 43MJ/kg.Calculatei) The indicated power
Solution
To calculate the indicated power, we need to use the formula for indicated power (IP) in a 4-stroke engine:
IP = (n * N * L * A * IMEP) / 2
where:
- n is the number of cylinders (4 in this case)
- N is the engine speed in revolutions per minute (2000 rpm)
- L is the stroke length in meters (91mm = 0.091m)
- A is the cylinder area, which can be calculated using the formula for the area of a circle (π * (d/2)^2), where d is the bore diameter (93mm = 0.093m)
- IMEP is the indicated mean effective pressure (850 kN/m^2 = 850000 N/m^2)
First, let's calculate the cylinder area (A):
A = π * (d/2)^2 A = π * (0.093/2)^2 A = 0.0068 m^2
Now, we can calculate the indicated power:
IP = (4 * 2000 * 0.091 * 0.0068 * 850000) / 2 IP = 11796.48 Watts or 11.8 kW
So, the indicated power of the engine is approximately 11.8 kW.
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