A uniform meterstick is balanced at its midpoint with several forces applied, as shown below. If the stick is in equilibrium, the magnitude of the force X in newtons (N) isGroup of answer choices50 N300 N200 N100 N

The diagram shows a metre stick suspended from its centre of gravity. A force of 4N acts on the stick at the 20cm mark. A force of FN acts on the stick at the 70 cm mark. The stick is balanced horizontally. Calculate force F.

A meterstick is supported by a knife-edge at the 50-cm mark. Doug hangs masses of 0.40 and 0.60 kg from the 5-cm and 70-cm marks, respectively. Where should Doug hang a third mass of 0.20 kg to keep the stick balanced?Select one:a.10 cmb.90 cmc.20 cmd.50 cme.80 cm

A meter stick is supported at the 50-cm mark. A 0.40 kg mass is hanging at the 20 cm mark and a 0.60 kg hanging at the 80-cm mark. Where should a third mass that weighs 0.30 kg be hung to keep the stick balanced?

Three masses are attached to a uniform MASSLESS meter stick, as shown in figure above.  The masses to the left of the fulcrum are m1 = 7.75kg and m2 = 9.2 kg. Find the mass that balances the system when it is attached at the right end of the stick. Round your answer to the nearest tenth decimal place

Force 𝐹1F 1​ : Magnitude of 10 N acting at an angle of 30∘30 ∘ from the positive x-axis.Force 𝐹2F 2​ : Magnitude of 15 N acting at an angle of 120∘120 ∘ from the positive x-axis.