Dimethyl ether, a useful organic solvent, is prepared in two steps. In the first step, carbon dioxide and hydrogen react to form methanol and water:CO2(g) + 3H2(g) → CH3OH(l) + H2O(l) =ΔH−131.kJIn the second step, methanol reacts to form dimethyl ether and water:2CH3OH(l) → CH3OCH3(g) + H2O(l) =ΔH8.kJCalculate the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and hydrogen from these reactions.Round your answer to the nearest kJ.kJ
Question
Dimethyl ether, a useful organic solvent, is prepared in two steps. In the first step, carbon dioxide and hydrogen react to form methanol and water:CO2(g) + 3H2(g) → CH3OH(l) + H2O(l) =ΔH−131.kJIn the second step, methanol reacts to form dimethyl ether and water:2CH3OH(l) → CH3OCH3(g) + H2O(l) =ΔH8.kJCalculate the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and hydrogen from these reactions.Round your answer to the nearest kJ.kJ
Solution
To calculate the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and hydrogen, we need to add the enthalpy changes of the two steps.
In the first step, the enthalpy change (ΔH) is -131 kJ. In the second step, the enthalpy change (ΔH) is 8 kJ.
To find the total enthalpy change, we add these two values together:
-131 kJ + 8 kJ = -123 kJ
So, the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and hydrogen is -123 kJ.
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