The total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4]
Question
The total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4]
Solution
The complex compound [Cu(NH3)4][PtCl4] has two parts: the cation [Cu(NH3)4]2+ and the anion [PtCl4]2-.
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The cation [Cu(NH3)4]2+ has a central metal atom (Cu) surrounded by four identical ligands (NH3). Therefore, it can only exist in one form and does not have any isomers.
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The anion [PtCl4]2- also has a central metal atom (Pt) surrounded by four identical ligands (Cl). Therefore, it can also only exist in one form and does not have any isomers.
Therefore, the complex compound [Cu(NH3)4][PtCl4] does not have any isomers. The total number of possible isomers for this complex compound is 1.
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