In an isosceles triangle, the base angles are equal. The vertex angle is 40°. Whatare the base angles of the triangle?
Question
In an isosceles triangle, the base angles are equal. The vertex angle is 40°. Whatare the base angles of the triangle?
Solution
Let's solve the problem step by step:
Step 1: Recall that in an isosceles triangle, the base angles are equal.
Step 2: Let's denote the measure of each base angle as x.
Step 3: Since the vertex angle is given as 40°, we can set up an equation:
x + x + 40° = 180° (the sum of angles in a triangle is 180°)
Step 4: Simplify the equation:
2x + 40° = 180°
Step 5: Subtract 40° from both sides of the equation:
2x = 180° - 40°
2x = 140°
Step 6: Divide both sides of the equation by 2:
x = 140° / 2
x = 70°
Step 7: Therefore, the base angles of the isosceles triangle are both 70°.
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