closed cylinder contains 20 g helium gas and 64 g oxygen gas exerting a pressure of 10 atm. Partial pressure of oxygen in the cylinder is
Question
closed cylinder contains 20 g helium gas and 64 g oxygen gas exerting a pressure of 10 atm. Partial pressure of oxygen in the cylinder is
Solution
To find the partial pressure of oxygen in the cylinder, we first need to find the mole fraction of oxygen.
Step 1: Find the number of moles of each gas.
The molar mass of helium (He) is approximately 4 g/mol and the molar mass of oxygen (O2) is approximately 32 g/mol.
Number of moles of He = mass/molar mass = 20g / 4g/mol = 5 moles Number of moles of O2 = mass/molar mass = 64g / 32g/mol = 2 moles
Step 2: Find the total number of moles.
Total moles = moles of He + moles of O2 = 5 moles + 2 moles = 7 moles
Step 3: Find the mole fraction of oxygen.
Mole fraction of O2 = moles of O2 / total moles = 2 moles / 7 moles = 0.286
Step 4: Find the partial pressure of oxygen.
Partial pressure of O2 = total pressure * mole fraction of O2 = 10 atm * 0.286 = 2.86 atm
So, the partial pressure of oxygen in the cylinder is 2.86 atm.
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