Reena walked from A to B in the East 10 feet. Then she turned to the right and walked 3 feet. Again she turned to the right and walked 14 feet. How far is she from A?57912None
Question
Reena walked from A to B in the East 10 feet. Then she turned to the right and walked 3 feet. Again she turned to the right and walked 14 feet. How far is she from A?57912None
Solution
Reena's journey can be visualized as a right-angled triangle.
- She first walked from A to B, 10 feet to the East. This forms the base of the triangle.
- Then she turned right and walked 3 feet. This forms the height of the triangle.
- Finally, she turned right again and walked 14 feet. This forms the hypotenuse of the triangle.
We are asked to find out how far she is from point A. This would be the length of the hypotenuse of the triangle.
According to the Pythagorean theorem, the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b). In mathematical terms, this is expressed as c² = a² + b².
Here, a = 10 feet (the distance she walked to the East), and b = 3 feet (the distance she walked to the South).
So, c² = (10)² + (3)² = 100 + 9 = 109.
Therefore, c = √109 = approximately 10.44 feet.
So, Reena is approximately 10.44 feet away from point A.
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