Ramanuj walked from “Tower A” to “Tower B” in the East 10 feet. Then she turned to the right and walked 3 feet. Again he turned to the right and walked 14 feet. How far is she from Tower A?4 feet
Question
Ramanuj walked from “Tower A” to “Tower B” in the East 10 feet. Then she turned to the right and walked 3 feet. Again he turned to the right and walked 14 feet. How far is she from Tower A?4 feet
Solution
Ramanuj initially walked 10 feet east from Tower A to Tower B. Then, she turned right and walked 3 feet. This means she is now 3 feet south of Tower B. When she turned right again and walked 14 feet, she moved west.
Since she initially moved 10 feet east, and then moved 14 feet west, she is now 4 feet west of Tower B (14 feet - 10 feet = 4 feet).
However, since she also moved 3 feet south, we need to calculate the straight-line distance (or the "as the crow flies" distance) from Tower A.
We can use the Pythagorean theorem to do this, which states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
So, if we let d be the distance from Tower A, we have:
d^2 = 4^2 + 3^2 d^2 = 16 + 9 d^2 = 25
Taking the square root of both sides gives:
d = 5
So, Ramanuj is 5 feet away from Tower A.
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