A A+3 B B-1Number of electrons present in the outermost shells of atoms A and Brespectively are

The question seems to be incomplete. However, I can provide a general approach to find the number of electrons in the outermost shell of an atom.

1. Identify the atomic number of the atom: The atomic number of an atom is equal to the number of protons in its nucleus. It also equals the number of electrons in the atom when it is in a neutral state (not ionized).

2. Determine the electron configuration: The electron configuration of an atom shows how the electrons are distributed among the various atomic orbitals. The first two electrons will go in the 1s orbital. The next two electrons go in the 2s orbital. The next six electrons will go in the 2p orbital. The next two electrons go in the 3s. The next six in the 3p. The next two in the 4s. The next ten in the 3d. And so on.

3. Find the outermost shell: The outermost shell of an atom, also known as the valence shell, is the highest energy level that contains electrons. In an electron configuration, it's the highest number 'n' that has electrons.

4. Count the electrons in the outermost shell: Once you've identified the outermost shell, count the number of electrons in that shell. This will be the number of electrons in the outermost shell of the atom.

For atom A and B, if you could provide the atomic numbers or the elements they represent, I could provide a more specific answer.