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I read 3/8 of a book on one day and 4/5 of the remainder on another day. If now there were 30 pages unread, the book contains:Options 240 pages 230 pages 340 pages 140 pages None of the above

Question

I read 3/8 of a book on one day and 4/5 of the remainder on another day. If now there were 30 pages unread, the book contains:Options 240 pages 230 pages 340 pages 140 pages None of the above

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Solution

Let's solve this step by step:

  1. Let's assume the total number of pages in the book is X.

  2. On the first day, 3/8 of the book was read. So, the remaining part of the book is 1 - 3/8 = 5/8.

  3. On the second day, 4/5 of the remaining part (which is 5/8 of the book) was read. So, the unread part of the book is 1 - 4/5 = 1/5.

  4. Therefore, the unread part of the book is 1/5 * 5/8 = 1/8 of the total book.

  5. According to the problem, this unread part is equal to 30 pages. So, we can set up the equation 1/8X = 30.

  6. Solving this equation for X gives us X = 30 * 8 = 240.

So, the book contains 240 pages.

This problem has been solved

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