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A step array is an array of integers where each element has a difference of at most k with its neighbor. Given a key x, we need to find the index value of x if multiple elements exist, and return the first occurrence of the key.

Question

A step array is an array of integers where each element has a difference of at most k with its neighbor. Given a key x, we need to find the index value of x if multiple elements exist, and return the first occurrence of the key.

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Solution

Sure, I can help with that. Here's a step-by-step guide on how to solve this problem:

  1. Initialize a variable i to 0. This will be used to iterate over the array.

  2. Start a while loop that continues as long as i is less than the length of the array.

  3. In the loop, check if the ith element of the array is equal to x. If it is, return i because we have found the first occurrence of x.

  4. If the ith element is not equal to x, calculate the absolute difference between the ith element and x, divide it by k and round it up to the nearest whole number. This will give us the minimum number of steps needed to reach x from the ith element. Increment i by this value.

  5. If the loop completes without finding x, return -1 to indicate that x is not in the array.

Here's how this algorithm can be implemented in Python:

import math

def find_index(arr, n, x, k):
    i = 0
    while (i < n):
        if (arr[i] == x):
            return i
        i = i + math.ceil(abs(arr[i]-x)/k)
    return -1

In this function, arr is the step array, n is the length of the array, x is the key we are looking for, and k is the maximum difference between neighboring elements in the array. The function returns the index of the first occurrence of x in the array, or -1 if x is not in the array.

This problem has been solved

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