Select the correct answerWhat will be the output of the following Python code?>>> ct={k: 'C' + str(k) for k in range(4)}>>> ctOptions{0: '0', 1: '1', 2: '2', 3: '3’}{0: 'C', 1: 'C', 2: 'C', 3: 'C'}{0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}An exception is thrown
Question
Select the correct answerWhat will be the output of the following Python code?>>> ct={k: 'C' + str(k) for k in range(4)}>>> ctOptions{0: '0', 1: '1', 2: '2', 3: '3’}{0: 'C', 1: 'C', 2: 'C', 3: 'C'}{0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}An exception is thrown
Solution
The correct answer is {0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}.
Here's the step by step explanation:
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The code is creating a dictionary using dictionary comprehension.
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The
for k in range(4)part is generating keys for the dictionary. It will generate numbers from 0 to 3. -
The
k: 'C' + str(k)part is generating values for each key. It's concatenating the string 'C' with the string representation of the key. -
So, for key 0, the value will be 'C' + '0' = 'C0'. For key 1, the value will be 'C' + '1' = 'C1', and so on.
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Therefore, the final dictionary will be {0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}.
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