(a) A car accelerates uniformly from 18km/h to 36km/h in 5s. Calculate:(i) acceleration (ii) distance covered by the car in that time.
Question
(a) A car accelerates uniformly from 18km/h to 36km/h in 5s. Calculate:(i) acceleration (ii) distance covered by the car in that time.
Solution
Sure, let's solve this step by step:
(i) Acceleration: First, we need to convert the speeds from km/h to m/s because the standard unit of acceleration is m/s². We know that 1 km/h is approximately equal to 0.278 m/s.
So, 18 km/h = 18 * 0.278 = 5 m/s And, 36 km/h = 36 * 0.278 = 10 m/s
Acceleration is defined as the change in velocity divided by the time taken for the change. It can be calculated using the formula:
Acceleration = (Final velocity - Initial velocity) / Time
Substituting the given values into the formula, we get:
Acceleration = (10 m/s - 5 m/s) / 5s = 1 m/s²
(ii) Distance covered: The distance covered by the car can be calculated using the formula:
Distance = Initial velocity * Time + 0.5 * Acceleration * (Time)²
Substituting the given values into the formula, we get:
Distance = 5 m/s * 5s + 0.5 * 1 m/s² * (5s)² = 25 m + 12.5 m = 37.5 m
So, the car covered a distance of 37.5 meters.
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