If f(x) = 2x-2, then what is the value of f(x+2) + f(x-2) when x=0?a.-8b.4c.-4d.8

To solve this problem, we first need to substitute x+2 and x-2 into the function f(x) = 2x - 2.

1. Calculate f(x+2): Substitute x+2 into the function, we get f(x+2) = 2*(x+2) - 2 = 2x + 4 - 2 = 2x + 2.

2. Calculate f(x-2): Substitute x-2 into the function, we get f(x-2) = 2*(x-2) - 2 = 2x - 4 - 2 = 2x - 6.

Then, we add f(x+2) and f(x-2) together:

f(x+2) + f(x-2) = (2x + 2) + (2x - 6) = 4x - 4.

Finally, substitute x = 0 into the equation 4x - 4, we get:

4*0 - 4 = -4.

So, the answer is c. -4.