The Lewis dot structure of the sulfite ion (SO3^2-) can be determined by following these steps:

1. Identify the total number of valence electrons. Sulfur (S) has 6 valence electrons and Oxygen (O) has 6 valence electrons. Since there are three oxygen atoms, we multiply 6 by 3 to get 18. Adding the 6 electrons from sulfur gives us 24.

2. Consider the charge of the ion. The sulfite ion has a charge of -2, which means there are 2 extra electrons. Add these to the total from step 1, giving us 26.

So, the correct Lewis dot formula of the sulfite ion has 26 valence electrons.

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The Lewis dot structure of the sulfite ion (SO3^2-) can be determined by following these steps:

1. Identify the total number of valence electrons. Sulfur (S) has 6 valence electrons and Oxygen (O) has 6 valence electrons. Since there are three oxygen atoms, we multiply 6 by 3 to get 18. Adding the 6 electrons from sulfur gives us 24.

2. Consider the charge of the ion. The sulfite ion has a charge of -2, which means there are 2 extra electrons. Add these to the total from step 1, giving us 26.

So, the correct Lewis dot formula of the sulfite ion has 26 valence electrons.

Knowee AI · Accepted Answer

The Lewis dot structure of the sulfite ion (SO3^2-) can be determined by following these steps:

1. Identify the total number of valence electrons. Sulfur (S) has 6 valence electrons and Oxygen (O) has 6 valence electrons. Since there are three oxygen atoms, we multiply 6 by 3 to get 18. Adding the 6 electrons from sulfur gives us 24.

2. Consider the charge of the ion. The sulfite ion has a charge of -2, which means there are 2 extra electrons. Add these to the total from step 1, giving us 26.

So, the correct Lewis dot formula of the sulfite ion has 26 valence electrons.

What is the total number of valence electrons in the correct Lewis dot formula of the sulfite ion?Group of answer choices24322630

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