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Suppose f(x) =1๐‘ฅx1โ€‹ then (๐‘“โˆ˜๐‘“โˆ˜๐‘“)(๐‘ฅ)(fโˆ˜fโˆ˜f)(x) =A.11๐‘ฅx1โ€‹ 1โ€‹ B.1๐‘ฅx1โ€‹ C.๐‘ฅ2x 2 D.1๐‘ฅ2x 2 1โ€‹ E.xSUBMITarrow_backPREVIOUS

Question

Suppose f(x) =1๐‘ฅx1โ€‹ then (๐‘“โˆ˜๐‘“โˆ˜๐‘“)(๐‘ฅ)(fโˆ˜fโˆ˜f)(x) =A.11๐‘ฅx1โ€‹ 1โ€‹ B.1๐‘ฅx1โ€‹ C.๐‘ฅ2x 2 D.1๐‘ฅ2x 2 1โ€‹ E.xSUBMITarrow_backPREVIOUS

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Solution

Entendido. Vamos resolver o problema passo a passo.

Dado f(x)=1x f(x) = \frac{1}{x} , precisamos encontrar (fโˆ˜fโˆ˜f)(x) (f \circ f \circ f)(x) .

  1. Primeiro, vamos calcular (fโˆ˜f)(x) (f \circ f)(x) : (fโˆ˜f)(x)=f(f(x)) (f \circ f)(x) = f(f(x)) Sabemos que f(x)=1x f(x) = \frac{1}{x} , entรฃo: f(f(x))=f(1x) f(f(x)) = f\left(\frac{1}{x}\right) Aplicando f f novamente: f(1x)=1(1x)=x f\left(\frac{1}{x}\right) = \frac{1}{\left(\frac{1}{x}\right)} = x Portanto, (fโˆ˜f)(x)=x (f \circ f)(x) = x .

  2. Agora, vamos calcular (fโˆ˜fโˆ˜f)(x) (f \circ f \circ f)(x) : (fโˆ˜fโˆ˜f)(x)=f((fโˆ˜f)(x)) (f \circ f \circ f)(x) = f((f \circ f)(x)) Jรก sabemos que (fโˆ˜f)(x)=x (f \circ f)(x) = x , entรฃo: f((fโˆ˜f)(x))=f(x) f((f \circ f)(x)) = f(x) E sabemos que f(x)=1x f(x) = \frac{1}{x} .

Portanto, (fโˆ˜fโˆ˜f)(x)=1x (f \circ f \circ f)(x) = \frac{1}{x} .

A resposta correta รฉ: B. 1x \frac{1}{x}

This problem has been solved

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