The sum of four consecutive integers is 1290.The greatest of them is?Options220760324NONE
Question
The sum of four consecutive integers is 1290.The greatest of them is?Options220760324NONE
Solution
Let's denote the four consecutive integers as x, x+1, x+2, and x+3.
Given that their sum is 1290, we can write the equation as:
x + (x+1) + (x+2) + (x+3) = 1290
Solving this equation:
4x + 6 = 1290
Subtract 6 from both sides:
4x = 1284
Divide by 4:
x = 321
So, the four consecutive numbers are 321, 322, 323, and 324.
Therefore, the greatest of them is 324. So, the correct option is 324.
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