Consider the dire t pro du t Z × V where Z is the group of integers (under ad-dition) and V is the Klein 4-group with elements {e, a, b, c} and multipli ation∗ dened by the table b elow:* e a b ce e a b ca a e c bb b c e ac c b a e(a) Find the order |Z × V |. [1 mark℄(b) Is Z × V ab elian? (Justify your answer.) [1 mark℄( ) Find the order of (0, a) and the order of (1, b)
Question
Consider the dire t pro du t Z × V where Z is the group of integers (under ad-dition) and V is the Klein 4-group with elements {e, a, b, c} and multipli ation∗ dened by the table b elow:* e a b ce e a b ca a e c bb b c e ac c b a e(a) Find the order |Z × V |. [1 mark℄(b) Is Z × V ab elian? (Justify your answer.) [1 mark℄( ) Find the order of (0, a) and the order of (1, b)
Solution
(a) The order of a direct product of two groups is the product of their orders. The order of the group of integers Z is infinite and the order of the Klein 4-group V is 4 (since it has 4 elements: {e, a, b, c}). Therefore, the order of the direct product Z × V is infinite × 4 = infinite.
(b) The group Z × V is abelian if and only if both Z and V are abelian. The group of integers Z under addition is abelian because the operation of addition is commutative. The Klein 4-group V is also abelian, as can be seen from the multiplication table: each row and column is a permutation of {e, a, b, c}, which means that the operation * is commutative. Therefore, the direct product Z × V is abelian.
(c) The order of an element in a direct product group is the least common multiple of the orders of the elements in the individual groups. The order of 0 in Z is infinite and the order of a in V is 2 (since aa = e), so the order of (0, a) in Z × V is the least common multiple of infinite and 2, which is infinite. The order of 1 in Z is infinite and the order of b in V is 2 (since bb = e), so the order of (1, b) in Z × V is the least common multiple of infinite and 2, which is infinite.
Similar Questions
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