Purple colour KMNO4 due to
Solution
The purple color of KMNO4 is due to the presence of manganese ions (Mn^2+) in the compound. When KMNO4 is dissolved in water, it dissociates into potassium ions (K+) and permanganate ions (MnO4^-). The permanganate ions are responsible for the purple color. This is because the permanganate ion absorbs light in the visible spectrum, particularly in the range of wavelengths corresponding to purple light. As a result, when light passes through a solution of KMNO4, the permanganate ions absorb certain wavelengths of light and reflect or transmit the remaining wavelengths, giving the solution a purple color.
Similar Questions
Purple colour of KMnO4 is dueto
Potassium permanganate (KMnO4) is a highly reactive inorganic salt that appears as granular dark purple crystals, nearly black in color. Due to its useful chemical properties and the fact that its reactions typically do not produce compounds that are toxic, KMnO4 is employed in a variety of applications, including use as a topical skin disinfectant, an antifungal agent, a fire starter, and a disinfectant for drinking water.KMnO4 is widely used as an alternative water treatment agent both to disinfect drinking water and to remove undesirable dissolved iron and sulfur compounds. The crystals are highly soluble in water and form bright pink aqueous solutions that provide a visual indication of the presence of KMnO4 treatment residual. As a drinking water disinfectant, a KMnO4 concentration of 1 mg/L is recommended unless higher levels of contamination are indicated by the absence of a pink residual.Industrial production of potassium permanganate is accomplished in two steps. In step 1, manganese(IV) oxide (MnO2) is heated with potassium hydroxide in the presence of oxygen to produce potassium manganate (K2MnO4), as outlined in Reaction 1.2 MnO2 + 4 KOH + O2 → 2 K2MnO4 + 2 H2OReaction 1In step 2, the potassium manganate is then converted into potassium permanganate electrochemically according to Reaction 2.2 K2MnO4 + 2 H2O → 2 KMnO4 + 2 KOH + H2Reaction 2 Question 43In Reaction 1 shown in the passage, the oxidizing agent is:A.K2MnO4, because potassium loses electrons.B.MnO2, because manganese gains electrons.C.KOH, because hydrogen loses electrons.D.O2, because oxygen gains electrons.
you recorded the endpoint volume and then noticed that the color had faded . . . . you did not add more KMnO4 solution?
KMNO4 ACT AS ______________ IN TIRATION.a.Self indicatorb.Internal indicatorc.pH indicatord.External indicator
KMNO4 ACT AS ______________ IN TIRATION.
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