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What is the magnitude of the vector a=[1,0,2,−1]?√2√62√3

Question

What is the magnitude of the vector a=[1,0,2,−1]?√2√62√3

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Solution

Para encontrar la magnitud del vector a=[1,0,2,1] \mathbf{a} = [1, 0, 2, -1] , se utiliza la fórmula de la magnitud de un vector en el espacio euclidiano, que es:

a=a12+a22+a32+a42 \|\mathbf{a}\| = \sqrt{a_1^2 + a_2^2 + a_3^2 + a_4^2}

Donde a1,a2,a3 a_1, a_2, a_3 y a4 a_4 son los componentes del vector a \mathbf{a} .

  1. Identificamos los componentes del vector a \mathbf{a} : a1=1,a2=0,a3=2,a4=1 a_1 = 1, \quad a_2 = 0, \quad a_3 = 2, \quad a_4 = -1

  2. Elevamos cada componente al cuadrado: a12=12=1 a_1^2 = 1^2 = 1 a22=02=0 a_2^2 = 0^2 = 0 a32=22=4 a_3^2 = 2^2 = 4 a42=12=1 a_4^2 = -1^2 = 1

  3. Sumamos los cuadrados de los componentes: 1+0+4+1=6 1 + 0 + 4 + 1 = 6

  4. Tomamos la raíz cuadrada de la suma: a=6 \|\mathbf{a}\| = \sqrt{6}

Por lo tanto, la magnitud del vector a \mathbf{a} es 6 \sqrt{6} .

This problem has been solved

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