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Select the correct answerWhat will be the output of the following Python code?>>> ct={k: 'C' + str(k) for k in range(4)}>>> ctOptionsAn exception is thrown{0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}{0: 'C', 1: 'C', 2: 'C', 3: 'C'}{0: '0', 1: '1', 2: '2', 3: '3’}

Question

Select the correct answerWhat will be the output of the following Python code?>>> ct={k: 'C' + str(k) for k in range(4)}>>> ctOptionsAn exception is thrown{0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}{0: 'C', 1: 'C', 2: 'C', 3: 'C'}{0: '0', 1: '1', 2: '2', 3: '3’}

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Solution

The correct answer is {0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}.

Here's the step by step explanation:

  1. The code is creating a dictionary using dictionary comprehension. The expression inside the curly braces {k: 'C' + str(k) for k in range(4)} is a dictionary comprehension.

  2. The for loop (for k in range(4)) will iterate over the numbers 0 to 3.

  3. For each iteration, it will create a key-value pair in the dictionary. The key is the current number (k) and the value is a string that starts with 'C' and ends with the string representation of the current number ('C' + str(k)).

  4. So, for the first iteration (k=0), it will add the key-value pair 0: 'C0' to the dictionary. For the second iteration (k=1), it will add 1: 'C1', and so on.

  5. The final dictionary will be {0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}.

This problem has been solved

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