To determine which point lies outside the circle, we can use the equation of a circle, which is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius. In this case, the center is at (0,0) and the radius is 5.

Let's calculate the distance from the center to each point:

A. (4.1, 1)
The distance is sqrt((4.1-0)² + (1-0)²) = sqrt(16.81 + 1) = sqrt(17.81) = 4.22 (approximately)

B. (4, 2)
The distance is sqrt((4-0)² + (2-0)²) = sqrt(16 + 4) = sqrt(20) = 4.47 (approximately)

C. (3.8, 3)
The distance is sqrt((3.8-0)² + (3-0)²) = sqrt(14.44 + 9) = sqrt(23.44) = 4.84 (approximately)

D. (2, 5)
The distance is sqrt((2-0)² + (5-0)²) = sqrt(4 + 25) = sqrt(29) = 5.39 (approximately)

So, the point that lies outside the circle is D. (2, 5) because its distance to the center is greater than the radius of the circle.

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To determine which point lies outside the circle, we can use the equation of a circle, which is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius. In this case, the center is at (0,0) and the radius is 5.

Let's calculate the distance from the center to each point:

A. (4.1, 1)
The distance is sqrt((4.1-0)² + (1-0)²) = sqrt(16.81 + 1) = sqrt(17.81) = 4.22 (approximately)

B. (4, 2)
The distance is sqrt((4-0)² + (2-0)²) = sqrt(16 + 4) = sqrt(20) = 4.47 (approximately)

C. (3.8, 3)
The distance is sqrt((3.8-0)² + (3-0)²) = sqrt(14.44 + 9) = sqrt(23.44) = 4.84 (approximately)

D. (2, 5)
The distance is sqrt((2-0)² + (5-0)²) = sqrt(4 + 25) = sqrt(29) = 5.39 (approximately)

So, the point that lies outside the circle is D. (2, 5) because its distance to the center is greater than the radius of the circle.

Knowee AI · Accepted Answer

To determine which point lies outside the circle, we can use the equation of a circle, which is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius. In this case, the center is at (0,0) and the radius is 5.

Let's calculate the distance from the center to each point:

A. (4.1, 1)
The distance is sqrt((4.1-0)² + (1-0)²) = sqrt(16.81 + 1) = sqrt(17.81) = 4.22 (approximately)

B. (4, 2)
The distance is sqrt((4-0)² + (2-0)²) = sqrt(16 + 4) = sqrt(20) = 4.47 (approximately)

C. (3.8, 3)
The distance is sqrt((3.8-0)² + (3-0)²) = sqrt(14.44 + 9) = sqrt(23.44) = 4.84 (approximately)

D. (2, 5)
The distance is sqrt((2-0)² + (5-0)²) = sqrt(4 + 25) = sqrt(29) = 5.39 (approximately)

So, the point that lies outside the circle is D. (2, 5) because its distance to the center is greater than the radius of the circle.

Which of the following points lies outside the circle with center (0,0) and radius 5 ?A.(4.1, 1)B.(4, 2)C.(3.8, 3)D.(2, 5)

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