The molecule CH3CH2COCH3 is acetone. The underlined and bolded element is the middle carbon atom, which is part of a carbonyl group (C=O).

In proton NMR spectroscopy, the splitting pattern of a signal depends on the number of neighboring protons (the "n+1" rule). However, there are no protons directly attached to the carbonyl carbon in acetone, so it would not appear in a proton NMR spectrum.

If we were considering a carbon-13 NMR spectrum, the carbonyl carbon would not be split by neighboring protons because carbon-13 NMR spectra are typically recorded with proton decoupling, which removes the splitting due to scalar coupling with protons.

So, if we must choose from the given options, "A singlet" would be the most appropriate, but please note that this is a somewhat misleading question because the carbonyl carbon in acetone would not give a signal in a proton NMR spectrum.

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The molecule CH3CH2COCH3 is acetone. The underlined and bolded element is the middle carbon atom, which is part of a carbonyl group (C=O).

In proton NMR spectroscopy, the splitting pattern of a signal depends on the number of neighboring protons (the "n+1" rule). However, there are no protons directly attached to the carbonyl carbon in acetone, so it would not appear in a proton NMR spectrum.

If we were considering a carbon-13 NMR spectrum, the carbonyl carbon would not be split by neighboring protons because carbon-13 NMR spectra are typically recorded with proton decoupling, which removes the splitting due to scalar coupling with protons.

So, if we must choose from the given options, "A singlet" would be the most appropriate, but please note that this is a somewhat misleading question because the carbonyl carbon in acetone would not give a signal in a proton NMR spectrum.

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The molecule CH3CH2COCH3 is acetone. The underlined and bolded element is the middle carbon atom, which is part of a carbonyl group (C=O).

In proton NMR spectroscopy, the splitting pattern of a signal depends on the number of neighboring protons (the "n+1" rule). However, there are no protons directly attached to the carbonyl carbon in acetone, so it would not appear in a proton NMR spectrum.

If we were considering a carbon-13 NMR spectrum, the carbonyl carbon would not be split by neighboring protons because carbon-13 NMR spectra are typically recorded with proton decoupling, which removes the splitting due to scalar coupling with protons.

So, if we must choose from the given options, "A singlet" would be the most appropriate, but please note that this is a somewhat misleading question because the carbonyl carbon in acetone would not give a signal in a proton NMR spectrum.

State the splitting pattern you would expect for the underlined (and bolded!) element in: CH3CH2COCH3Group of answer choicesA quartetA singletA tripletA doublet

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