Assuming a mass of 0.04 g, what is the power exerted by the electrical forces on a fragment of fiber if the fragment has a velocity of 200 mm/s, 10 ms after ejection? A.5 x 10-10 WB.1 x 10-8 WC.2 x 10-5 WD.8 x 10-5 W

To solve this problem, we need to use the formula for power, which is work done per unit time or the rate of doing work. However, we don't have direct information about the work done.

But we know that work done is equal to the change in kinetic energy (Work-Energy Theorem). So, we can find the work done by finding the change in kinetic energy of the fiber fragment.

Step 1: Convert all units to the standard SI units. The mass should be in kg and velocity should be in m/s. So, 0.04 g = 0.04 x 10^-3 kg and 200 mm/s = 0.2 m/s.

Step 2: Calculate the initial kinetic energy (at the time of ejection, t=0). Since we don't have any information about the initial velocity, let's assume it to be zero. So, initial kinetic energy = 0.5 * mass * (initial velocity)^2 = 0.5 * 0.04 x 10^-3 kg * (0 m/s)^2 = 0 J.

Step 3: Calculate the final kinetic energy (10 ms after ejection). Final kinetic energy = 0.5 * mass * (final velocity)^2 = 0.5 * 0.04 x 10^-3 kg * (0.2 m/s)^2 = 0.0008 J.

Step 4: Find the work done, which is the change in kinetic energy = final kinetic energy - initial kinetic energy = 0.0008 J - 0 J = 0.0008 J.

Step 5: Calculate power, which is work done per unit time = 0.0008 J / 10 x 10^-3 s = 0.08 W.

So, none of the given options (A, B, C, D) match the calculated power. Please check the question again, there might be a mistake in the given options or the given data.