x^{-\frac{2}{3}}=7\frac{1}{9}
Question
x^{-\frac{2}{3}}=7\frac{1}{9}
Solution
Sure, let's solve the equation step by step.
The given equation is: x^(-2/3) = 7 1/9
First, let's convert the mixed number 7 1/9 to an improper fraction.
7 1/9 = 64/9
So, the equation becomes: x^(-2/3) = 64/9
To get rid of the negative exponent, we can take the reciprocal of both sides:
x^(2/3) = 9/64
Now, to solve for x, we need to get rid of the fraction in the exponent. We can do this by raising both sides of the equation to the power of 3/2:
(x^(2/3))^(3/2) = (9/64)^(3/2)
This simplifies to:
x = (9/64)^(3/2)
To simplify further, we can take the square root of the numerator and denominator separately, and then cube the result:
x = ((√9)/ (√64))^3
x = (3/8)^3
x = 27/512
So, the solution to the equation x^(-2/3) = 7 1/9 is x = 27/512.
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