Calculate the energy required to heat 176.0mg of ammonia from 53.8°C to 64.4°C. Assume the specific heat capacity of ammonia under these conditions is ·4.70J·g−1K−1 . Be sure your answer has the correct number of significant digits.
Question
Calculate the energy required to heat 176.0mg of ammonia from 53.8°C to 64.4°C. Assume the specific heat capacity of ammonia under these conditions is ·4.70J·g−1K−1 . Be sure your answer has the correct number of significant digits.
Solution
To calculate the energy required to heat a substance, we can use the formula:
q = mcΔT
where:
- q is the heat energy,
- m is the mass of the substance,
- c is the specific heat capacity of the substance, and
- ΔT is the change in temperature.
Given:
- m = 176.0 mg = 0.176 g (since 1 g = 1000 mg),
- c = 4.70 J·g−1K−1, and
- ΔT = 64.4°C - 53.8°C = 10.6 K (since a change of 1°C is equal to a change of 1 K).
Substituting these values into the formula, we get:
q = (0.176 g) * (4.70 J·g−1K−1) * (10.6 K) = 8.7 J
So, the energy required to heat 176.0 mg of ammonia from 53.8°C to 64.4°C is approximately 8.7 J.
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