It is recommended that women over 40 have a mammogram annually. A recent reportindicated that if a woman has annual mammograms over a 10-year period, there is a60% probability that there will be at least one false-positive result. If the annual testresults are independent, what is the probability that in any one year a mammogram willproduce a false-positive result?

The image presents a scenario for calculating the probability that a woman between the ages of 50 and 59 has breast cancer given that she has a positive mammogram. The information provided is as follows: - 86.6 of every 1000 women without cancer get a false positive result. - 1.1 of every 1000 women with cancer get a false negative result. - 1 in 38 women will develop breast cancer. To solve this, we can use Bayes' theorem, which relates the conditional and marginal probabilities of random events: P(A|B) = [P(B|A) * P(A)] / P(B) Where: - P(A) is the probability of having breast cancer (A). - P(B) is the probability of a positive mammogram (B). - P(B|A) is the probability of a positive mammogram given breast cancer. - P(A|B) is the probability of having breast cancer given a positive mammogram. First, we need to find the probabilities: P(A) = Probability of having breast cancer = 1/38 ≈ 0.0263 (since 1 in 38 women develop breast cancer) P(B|A) = Probability of a positive mammogram given breast cancer = 1 - Probability of a false negative = 1 - (1.1/1000) = 0.9989P(B|~A) = Probability of a positive mammogram given no breast cancer = Probability of a false positive = 86.6/1000 = 0.0866P(~A) = Probability of not having breast cancer = 1 - P(A) ≈ 0.9737Now, we need to find P(B), the total probability of a positive mammogram: P(B) = P(B|A) * P(A) + P(B|~A) * P(~A) P(B) = (0.9989 * 0.0263) + (0.0866 * 0.9737) Calculating P(B): P(B) = (0.9989 * 0.0263) + (0.0866 * 0.9737) P(B) = 0.02626717 + 0.08431722P(B) = 0.11058439Now we can use Bayes' theorem to find P(A|B): P(A|B) = [P(B|A) * P(A)] / P(B) P(A|B) = (0.9989 * 0.0263) / 0.11058439P(A|B) = 0.02626717 / 0.11058439P(A|B) ≈ 0.2375So, the probability that a woman between the ages of 50 and 59 has breast cancer given she has a positive mammogram is approximately 0.2375, or 23.75% when rounded to four decimal places.

Suppose that a certain diagnostic screening programme has the probability of 0.023 ofmissing a positive diagnosis. In a sample of 100 cases independent of each other, whatis the probability that(i) Exactly 3 cases were undiagnosed?(ii) At least 2 cases were undiagnosed?

What proportion of breast cancer is theoretically preventable through changes in lifestyle among women in the US?Question 2Answera.All; annual mammography will detect all or most breast cancers in womenb.Approximately two-thirdsc.Approximately one-thirdd.Approximately one-half

It is known that a rare disease affects 1% of the population. A medical test for this disease is 99% effective, which means that if you have the disease, there is a 99% chance that the test will be positive, and if you do not have the disease, there is a 99% chance that the test will be negative.If you take the medical test and result is positive, what is the chance that you have the disease?Hint: consider a cohort of 10000 people and calculate P(having the disease AND test is positive) and P(not having the disease AND test is positive)Group of answer choices0.750.990.010.5

Which of the following statements about breast cancer in women is most accurate?Group of answer choicesBreast cancer is the most deadly illness for women.Each year in the United States approximately 275,000 women are diagnosed with breast cancer, and approximately 42,000 die from the disease.Experts recommend that women examine their breasts every month at the time of their menstrual period.Asian American women and European American women are equally likely to have regular mammograms.