Write a query to display all details of the station whose name starts with the letter 'K'. Display the records in ascending order based on the name.Note:1. Display all the columns present in the station table.2. Specify the condition and retrieve the correct rows in the result(condition need to be specified on name column).3. You can compare your executed result with the sample output given below.4. Order by is mandatorySample output:
Question
Write a query to display all details of the station whose name starts with the letter 'K'. Display the records in ascending order based on the name.Note:1. Display all the columns present in the station table.2. Specify the condition and retrieve the correct rows in the result(condition need to be specified on name column).3. You can compare your executed result with the sample output given below.4. Order by is mandatorySample output:
Solution
The query you're looking for would look something like this:
SELECT *
FROM station
WHERE name LIKE 'K%'
ORDER BY name ASC;
Here's what this query does, step by step:
-
SELECT * FROM station: This part of the query selects all columns from thestationtable. -
WHERE name LIKE 'K%': This is the condition that filters the results. TheLIKEkeyword is used in SQL to search for a specified pattern in a column. In this case, it's looking for any station names that start with 'K'. The '%' symbol is a wildcard character that can be used to define wildcards (left and right truncation) in conjunction with theLIKEoperator. -
ORDER BY name ASC: This part of the query sorts the results in ascending order (ASC) by thenamecolumn. If you wanted to sort the results in descending order, you could useDESCinstead ofASC.
So, this query will return all details of stations whose names start with 'K', sorted in ascending order by name.
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