Use inductive reasoning to decide whether each statement is true. a. The sum of two odd counting numbers is always an odd counting number. b. The product of two odd counting numbers is always an odd counting number.
Question
Use inductive reasoning to decide whether each statement is true. a. The sum of two odd counting numbers is always an odd counting number. b. The product of two odd counting numbers is always an odd counting number.
Solution
a. The statement is false. Let's use inductive reasoning to prove this. Take two odd numbers, for example 1 and 3. The sum of these two numbers is 4, which is an even number. Therefore, the sum of two odd counting numbers is not always an odd counting number, it is always an even counting number.
b. The statement is true. Again, let's use inductive reasoning to prove this. Take two odd numbers, for example 3 and 5. The product of these two numbers is 15, which is an odd number. Therefore, the product of two odd counting numbers is always an odd counting number.
Similar Questions
Use inductive reasoning to decide whether the statement is true or false. Make an example or a counterexample to supplement your answer.Write your answer in a piece of paper, take a picture of it and upload it here. Include your name and section. The product of an odd counting number and an even counting number is always an even counting number.
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6. Use a direct proof to show that the sum of two odd integers is even.7. Use a direct proof to show that the sum of two even integers is even Show that if n is an integer andn3 + 5 is odd, then n is even usinga) a proof by contraposition.b) a proof by contradiction.8. Prove that if n is a positive integer, then n is odd if and only if 5n + 6 is odd.9. Find a counterexample to the statement that every positive integer can be written as the sum of thesquares of three integers.
For each of the following statements, either prove that the statement is true, or finda counterexample to show that the statement is false and explain your reasoning.(a) For each integer n, n is even if and only if 6n + 4 is even.(b) For all integers ℓ, m, n, if ℓ + m is odd and ℓ + n is even, then m + n is odd.
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