Mason is getting quotes from two different landscaping companies to put river rock along one side of his house at a depth of 0.5 foot. The surface area of the space he wishes to install rock in is rectangular and has a length that is eight times its width.The first company charges $3.50 per cubic foot of rock and $80 for delivery. The second company charges $2.50 per cubic foot of rock and $120 for delivery.Which system of equations can be used to determine the value of the width, x, at which the cost of the two companies, y, is the same? A. 𝑦=28𝑥3+80𝑦=29𝑥3+120 B. 𝑦=3.5𝑥3+80𝑦=2.5𝑥3+120 C. 𝑦=28𝑥2+80𝑦=20𝑥2+120 D. 𝑦=14𝑥2+80𝑦=10𝑥2+120
Question
Mason is getting quotes from two different landscaping companies to put river rock along one side of his house at a depth of 0.5 foot. The surface area of the space he wishes to install rock in is rectangular and has a length that is eight times its width.The first company charges 80 for delivery. The second company charges 120 for delivery.Which system of equations can be used to determine the value of the width, x, at which the cost of the two companies, y, is the same? A. 𝑦=28𝑥3+80𝑦=29𝑥3+120 B. 𝑦=3.5𝑥3+80𝑦=2.5𝑥3+120 C. 𝑦=28𝑥2+80𝑦=20𝑥2+120 D. 𝑦=14𝑥2+80𝑦=10𝑥2+120
Solution
First, we need to find the volume of the rock needed. Since the depth is 0.5 foot and the area is a rectangle with length eight times its width, the volume in cubic feet is 0.5x(8x) = 4x^2.
The first company charges 80 for delivery. So the total cost from the first company is y = 3.5*(4x^2) + 80 = 14x^2 + 80.
The second company charges 120 for delivery. So the total cost from the second company is y = 2.5*(4x^2) + 120 = 10x^2 + 120.
Therefore, the system of equations that can be used to determine the value of the width, x, at which the cost of the two companies, y, is the same is:
y = 14x^2 + 80 y = 10x^2 + 120
So, the correct answer is D. 𝑦=14𝑥2+80, 𝑦=10𝑥2+120.
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