Here is a step-by-step guide to solve the programming task:

1. Initialize an empty dictionary `frequency_map` to store the frequency of each digit.

2. Convert the input integer `n` to a string to be able to iterate over each digit. This can be done using the `str()` function.

3. Create a while loop that continues as long as `n` is not equal to 0.

4. Inside the loop, calculate the last digit of `n` by taking `n` modulo 10. This can be done using the `%` operator.

5. Check if the last digit is already a key in `frequency_map`. If it is, increment the value associated with this key by 1. If it's not, add a new key-value pair to the dictionary with the key being the last digit and the value being 1.

6. Reduce `n` by removing its last digit. This can be done by performing integer division by 10 using the `//` operator.

7. Repeat steps 4-6 until `n` is equal to 0.

8. After the loop ends, `frequency_map` will contain the frequency of each digit present in `n`.

Here is a Python code snippet that implements the above steps:

```python
def digit_frequencies(n):
frequency_map = {}
while n != 0:
digit = n % 10
if digit in frequency_map:
frequency_map[digit] += 1
else:
frequency_map[digit] = 1
n = n // 10
return frequency_map
```

This function takes an integer `n` as input and returns a dictionary `frequency_map` that contains the frequency of each digit in `n`.

Question

Here is a step-by-step guide to solve the programming task:

1. Initialize an empty dictionary `frequency_map` to store the frequency of each digit.

2. Convert the input integer `n` to a string to be able to iterate over each digit. This can be done using the `str()` function.

3. Create a while loop that continues as long as `n` is not equal to 0.

4. Inside the loop, calculate the last digit of `n` by taking `n` modulo 10. This can be done using the `%` operator.

5. Check if the last digit is already a key in `frequency_map`. If it is, increment the value associated with this key by 1. If it's not, add a new key-value pair to the dictionary with the key being the last digit and the value being 1.

6. Reduce `n` by removing its last digit. This can be done by performing integer division by 10 using the `//` operator.

7. Repeat steps 4-6 until `n` is equal to 0.

8. After the loop ends, `frequency_map` will contain the frequency of each digit present in `n`.

Here is a Python code snippet that implements the above steps:

```python
def digit_frequencies(n):
    frequency_map = {}
    while n != 0:
        digit = n % 10
        if digit in frequency_map:
            frequency_map[digit] += 1
        else:
            frequency_map[digit] = 1
        n = n // 10
    return frequency_map
```

This function takes an integer `n` as input and returns a dictionary `frequency_map` that contains the frequency of each digit in `n`.

Knowee AI · Accepted Answer