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What will be the output of the following Python code?l=[1, 0, 2, 0, 'hello', '', []]print(list(filter(bool, l)))OptionsError[1, 0, 2, ‘hello’, ”, [ ]][1, 2, ‘hello’][1, 0, 2, 0, ‘hello’, ”, [ ]]

Question

What will be the output of the following Python code?l=[1, 0, 2, 0, 'hello', '', []]print(list(filter(bool, l)))OptionsError[1, 0, 2, ‘hello’, ”, [ ]][1, 2, ‘hello’][1, 0, 2, 0, ‘hello’, ”, [ ]]

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Solution

The output of the given Python code will be [1, 2, 'hello'].

Here's the step by step explanation:

  1. The given list l contains various elements - integers, strings, and an empty list.

  2. The filter() function in Python takes in a function and a list as arguments. This method constructs an iterator from elements of the input list for which the function returns true.

  3. In this case, the function used is bool(). The bool() function converts a value to boolean (True or False) using the standard truth testing procedure.

  4. For the bool() function, zero values (0, 0.0, 0j), empty collections (like an empty list []), and False are considered False, everything else is considered True.

  5. So, when filter(bool, l) is executed, it filters out all elements in the list l that return False when passed to the bool() function.

  6. Therefore, the elements 0, '' (empty string), and [] (empty list) are removed from the list l.

  7. The remaining elements are 1, 2, and 'hello', which are printed out. Hence, the output is [1, 2, 'hello'].

This problem has been solved

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