Dr K Sheedy writes a script for Slow-K, 2 tablets bd. How many millimoles of K+ does the patient receive daily?Data:Each Slow-K tablet contains 600 mg KClMW (KCl) = 74.55

To answer this question, we need to follow these steps:

1. First, we need to determine the amount of KCl in two tablets since the prescription is 2 tablets twice a day (bd). Each Slow-K tablet contains 600 mg of KCl, so 2 tablets contain 1200 mg. Since the prescription is for twice a day, the total daily amount is 1200 mg * 2 = 2400 mg.

2. Next, we need to convert this amount from milligrams to grams because the molecular weight we have is in grams. We know that 1 gram = 1000 milligrams, so 2400 mg = 2.4 grams.

3. Now, we need to calculate the number of moles of KCl in 2.4 grams. We can do this using the formula: number of moles = mass (in grams) / molecular weight. The molecular weight of KCl is 74.55, so the number of moles in 2.4 grams is 2.4 / 74.55 = 0.032 moles.

4. Since KCl is composed of one potassium ion (K+) and one chloride ion (Cl-), one mole of KCl will produce one mole of K+. Therefore, the number of moles of K+ in 2.4 grams of KCl is also 0.032 moles.

5. Finally, we need to convert moles to millimoles because the question asks for the answer in millimoles. We know that 1 mole = 1000 millimoles, so 0.032 moles = 32 millimoles.

So, the patient receives 32 millimoles of K+ daily.