𝑎−24=7𝑎−24=7The first step to undo the operations in this equation is to multiply both sides by 4, which gives:𝑎4=7𝑎4=7𝑎−8=28𝑎−8=284𝑎−2=284𝑎−2=284𝑎−8=284𝑎−8=28𝑎−2=28

What values of 𝑒e and 𝑓f make both of these equations true? 2𝑓2f==𝑒+6e+6𝑓−3𝑒f−3e==33

Solve 4∣𝑥+5∣+8=244∣x+5∣+8=24.

Solve the following equation:(𝑥−2)2+(𝑥+1)2=(𝑥+4)2𝑥= 7

∣2a−15∣=7

Solve ∣7𝑥+42∣=14𝑥∣7x+42∣=14x. Identify the solution and an extraneous solution.