If body is an electron moving around nucleus in orbit with radius 10-10 m. Calculate the minimum possiblenon zero value of velocity of an electron (NB! Electron is a point particle)

To calculate the minimum non-zero value of velocity of an electron, we need to use the principles of quantum mechanics. According to the Heisenberg Uncertainty Principle, the uncertainty in position (Δx) and momentum (Δp) of a particle is given by:

Δx * Δp ≥ h/4π

where h is Planck's constant (6.62607015 × 10^-34 m^2 kg / s).

In this case, the electron is moving in a circular orbit of radius 10^-10 m, so we can consider the uncertainty in position to be approximately the diameter of the orbit, i.e., Δx = 2 * 10^-10 m.

The uncertainty in momentum (Δp) can be expressed in terms of mass (m) and velocity (v) as Δp = m * Δv. For an electron, the mass is approximately 9.11 * 10^-31 kg.

Substituting these values into the Heisenberg Uncertainty Principle gives:

2 * 10^-10 m * 9.11 * 10^-31 kg * Δv ≥ 6.62607015 × 10^-34 m^2 kg / s / 4π

Solving for Δv gives the minimum non-zero value of the velocity of the electron.