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The average of 9z numbers is 12z. If 4z-2 is subtracted from each, then the new average is?Options12z + 28z + 210z - 28z - 2

Question

The average of 9z numbers is 12z. If 4z-2 is subtracted from each, then the new average is?Options12z + 28z + 210z - 28z - 2

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Solution

The average of a set of numbers is calculated by summing all the numbers and dividing by the count of numbers. In this case, the average of 9z numbers is 12z, which means the total sum of the numbers is 9z * 12z = 108z^2.

If 4z-2 is subtracted from each number, the total amount subtracted from the sum is (4z-2) * 9z = 36z^2 - 18z.

So, the new sum of the numbers is 108z^2 - (36z^2 - 18z) = 72z^2 + 18z.

The new average is this sum divided by the count of numbers, which is 9z. So, the new average is (72z^2 + 18z) / 9z = 8z + 2.

So, the correct option is 8z + 2.

This problem has been solved

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