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The ratio of James to Nicholas's savings was 4 : 7 at first. After James saved another $166 and Nicholas saved another $43, James had twice of Nicholas. How much did James have in the end?

Question

The ratio of James to Nicholas's savings was 4 : 7 at first. After James saved another 166andNicholassavedanother166 and Nicholas saved another 43, James had twice of Nicholas. How much did James have in the end?

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Solution

Let's solve this step by step:

Step 1: Let's assume the initial amount of savings James had was 4x and Nicholas had was 7x.

Step 2: According to the problem, after saving some more money, James had twice the amount of Nicholas. So, we can write this as: 4x + 166 = 2(7x + 43)

Step 3: Simplify the equation: 4x + 166 = 14x + 86

Step 4: Rearrange the equation to find the value of x: 14x - 4x = 166 - 86, which simplifies to 10x = 80

Step 5: Solve for x: x = 80 / 10 = 8

Step 6: Now that we know x = 8, we can find out how much James had in the end. Substitute x = 8 into the equation for James's savings: 4x + 166 = 4*8 + 166 = 32 + 166 = $198

So, James had $198 in the end.

This problem has been solved

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