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A BCD digit to display multiple of 5 requires hardware of(A) 2 BCD display(B) 4 NOT, 2 BCD display(C) 2 XOR, 2 BCD display(D) 4 AND, 2 BCD display

Question

A BCD digit to display multiple of 5 requires hardware of(A) 2 BCD display(B) 4 NOT, 2 BCD display(C) 2 XOR, 2 BCD display(D) 4 AND, 2 BCD display

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Solution

The answer to your question is (B) 4 NOT, 2 BCD display.

Here's the step-by-step explanation:

  1. A BCD (Binary Coded Decimal) is a system of writing numbers where each digit is represented by a fixed number of binary digits, or bits.

  2. In this case, we want to display multiples of 5. The BCD representation of 5 is 0101.

  3. To display multiples of 5, we need to check if the last digit of the BCD number is 5. This can be done using NOT gates.

  4. A NOT gate is a digital logic gate that inverts the input it receives. If the input is 1, the output is 0 and vice versa.

  5. We need 4 NOT gates because the BCD representation of 5 has 4 bits.

  6. We also need 2 BCD displays to display the multiples of 5.

So, the correct answer is (B) 4 NOT, 2 BCD display.

This problem has been solved

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