The half-life of Lead-218 is 0.25 minutes, which means that half of the initial amount decays every 0.25 minutes. Therefore, every minute, the amount of Lead-218 decreases by a factor of (1/2)^(4), or 1/16.

This means that each minute, 1 - 1/16 = 15/16 of the initial amount remains.

Therefore, the fraction that decays away each minute is 1 - 15/16 = 1/16.

To express this as a percentage, we multiply by 100 to get (1/16)*100 = 6.25%.

So, approximately 6.25% of the sample decays away every minute.

Question

The half-life of Lead-218 is 0.25 minutes, which means that half of the initial amount decays every 0.25 minutes. Therefore, every minute, the amount of Lead-218 decreases by a factor of (1/2)^(4), or 1/16.

This means that each minute, 1 - 1/16 = 15/16 of the initial amount remains.

Therefore, the fraction that decays away each minute is 1 - 15/16 = 1/16.

To express this as a percentage, we multiply by 100 to get (1/16)*100 = 6.25%.

So, approximately 6.25% of the sample decays away every minute.

Knowee AI · Accepted Answer

The half-life of Lead-218 is 0.25 minutes, which means that half of the initial amount decays every 0.25 minutes. Therefore, every minute, the amount of Lead-218 decreases by a factor of (1/2)^(4), or 1/16.

This means that each minute, 1 - 1/16 = 15/16 of the initial amount remains.

Therefore, the fraction that decays away each minute is 1 - 15/16 = 1/16.

To express this as a percentage, we multiply by 100 to get (1/16)*100 = 6.25%.

So, approximately 6.25% of the sample decays away every minute.

The half-life of Lead-218 is 0.25 minute. This means that the amount of Lead-218 left from an initial sample of 100 mg can be modeled by A(t)=100(12)4t𝐴𝑡=100124𝑡 , where t is the number of minutes that have passed. What percent of the sample decays away every minute?

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