Write a program to check two strings are anagram or not.

Sure, here is a Python program that checks if two strings are anagrams:

def check_anagram(str1, str2):
    # Remove spaces and convert to lower case
    str1 = str1.replace(" ", "").lower()
    str2 = str2.replace(" ", "").lower()

    # Check if both strings have the same length
    if len(str1) != len(str2):
        return False

    # Create a count dictionary for each string
    count1 = {}
    count2 = {}

    # Count the frequency of each character in the first string
    for char in str1:
        if char in count1:
            count1[char] += 1
        else:
            count1[char] = 1

    # Count the frequency of each character in the second string
    for char in str2:
        if char in count2:
            count2[char] += 1
        else:
            count2[char] = 1

    # Compare the count dictionaries
    if count1 == count2:
        return True
    else:
        return False

# Test the function
print(check_anagram("listen", "silent"))  # Should print True
print(check_anagram("hello", "world"))  # Should print False

This program works by counting the frequency of each character in both strings and comparing these counts. If the counts are the same for all characters, then the strings are anagrams.

Sure, here is a Python program that checks if two strings are anagrams:

def check_anagram(str1, str2):
    # Remove spaces and convert to lower case
    str1 = str1.replace(' ', '').lower()
    str2 = str2.replace(' ', '').lower()

    # Check if both strings have the same length
    if len(str1) != len(str2):
        return False

    # Create a count dictionary for each string
    count1 = {}
    count2 = {}

    # Count the frequency of each character in the first string
    for char in str1:
        if char in count1:
            count1[char] += 1
        else:
            count1[char] = 1

    # Count the frequency of each character in the second string
    for char in str2:
        if char in count2:
            count2[char] += 1
        else:
            count2[char] = 1

    # Compare the count dictionaries
    if count1 == count2:
        return True
    else:
        return False

# Test the function
print(check_anagram('listen', 'silent'))  # Returns: True
print(check_anagram('hello', 'world'))  # Returns: False

This program works by counting the frequency of each character in both strings and comparing these counts. If the counts are the same for all characters, then the strings are anagrams.